NFACTOR - N-Factorful
A number is called n-factorful if it has exactly n distinct prime factors. Given positive integers a, b, and n, your task is to find the number of integers between a and b, inclusive, that are n-factorful. We consider 1 to be 0-factorful.
Input
Your input will consist of a single integer T followed by a newline and T test cases. Each test case consists of a single line containing integers a, b, and n as described above.
T > 10000
1 ≤ a ≤ b ≤ 106
0 ≤ n ≤ 10
Output
Output for each test case one line containing the number of n-factorful integers in [a, b].
Example
Input: 5 1 3 1 1 10 2 1 10 3 1 100 3 1 1000 0 Output: 2 2 0 8 1
hide comments
minhthai:
2016-02-05 13:25:15
such a nice problem! Be careful with your "limit" though :) |
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dwij28:
2016-01-06 06:57:55
Amazing ! If anyone ever asks me the list of best questions on SPOJ, this one is gonna rank very very high. Several TLE's before AC with 0.09 seconds. I applied memorization, 2D vectors, adapted sieve of eratosthenes, fast i-o, etc before finally realizing that my mistake was that i was iterating through all elements in (a, b) while using memorization. Used the std::upper_bound and std::lower_bound functions to finally get the green tick. |
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Md.Mahmudul Hasan:
2015-12-01 01:22:50
use 2d vector and push number in vector like vector[ factor] .push_back(number) and find upper bound and lower bound and res=upper_bound-lower_bound. |
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SangKuan:
2015-10-27 10:38:37
Great problem |
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newbie:
2015-10-20 06:41:12
Got AC in 0.64.
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robin_0:
2015-08-24 10:05:54
Wonderful Problem =D
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:.Mohib.::
2015-06-27 22:08:14
Very Nice problem!! |
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kp:
2015-06-26 10:11:17
learnt a lot.. awesome problem |
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[Mayank Pratap]:
2015-06-12 06:16:50
Finally ....After many TLEs I got AC ... :) |
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Aditya Kumar:
2015-05-31 11:13:57
Think simple
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Added by: | periclesmachado |
Date: | 2011-01-30 |
Time limit: | 1.879s-2.484s |
Source limit: | 50000B |
Memory limit: | 1536MB |
Cluster: | Cube (Intel G860) |
Languages: | All except: ASM64 |
Resource: | Facebook Hacker Cup 2011 Round 1C |