BITMAP - Bitmap

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There is given a rectangular bitmap of size n×m. Each pixel of the bitmap is either white or black, but at least one is white. The pixel in i-th line and j-th column is called the pixel (i,j). The distance between two pixels p1 = (i1, j1) and p2 = (i2, j2) is defined as:

d(p1, p2) = |i1 - i2|+|j1 - j2|.

Task

Write a program which:

  • reads the description of the bitmap from the standard input,
  • for each pixel, computes the distance to the nearest white pixel,
  • writes the results to the standard output.

Input

The number of test cases t is in the first line of input, then t test cases follow separated by an empty line. In the first line of each test case there is a pair of integer numbers n, m separated by a single space, 1 ≤ n ≤ 182, 1 ≤ m ≤ 182. In each of the following n lines of the test case exactly one zero-one word of length m, the description of one line of the bitmap, is written. On the j-th position in the line (i+1), 1 ≤ i ≤ n, 1 ≤ j ≤ m, is '1' if, and only if the pixel (i, j) is white.

Output

In the i-th line for each test case, 1 ≤ i ≤ n, there should be written m integers f(i, 1) ... f(i, m) separated by single spaces, where f(i, j) is the distance from the pixel (i, j) to the nearest white pixel.

Example

Sample input:
1
3 4
0001
0011
0110

Sample output:
3 2 1 0
2 1 0 0
1 0 0 1

hide comments
Vinay Sharma: 2016-09-01 15:56:10

Why does it give SIGSEGV ?

imwrkhrd: 2016-08-28 22:46:47

n/m seems to be bigger than 182

hamzaziadeh: 2016-08-13 01:37:05

It gives me re tho its working with me?

cnexans: 2016-08-08 19:09:30

Guessing that it is a metric space

sarthak_8: 2016-08-07 10:10:24

60th on SPOJ. AC in 0.08 sec. Good question. Learnt something new. Must do.

Last edit: 2016-08-07 10:16:38
Dushyant Singh: 2016-07-26 13:35:27

Weird. Declaring 2D char array inside main gives RE and declaring it globally gives AC. o_O

UPD --> More weird thing. If I declare 2D char array before other variables AC else it gives RE! WTF! x_x

Last edit: 2016-07-26 13:48:09
sonali9696: 2016-07-19 17:03:35

My first bfs question ^_^

SANDEEP KUMAR: 2016-07-14 05:34:47

cakewalk, totally flooded it...

iharsh234: 2016-07-09 21:52:18

with simple bfs AC modifies code a bit series of RE comes _/\_

Last edit: 2016-07-09 21:53:48
Deepak : 2016-07-04 13:44:51

finally AC after a TLE...now in 0.08!!


Added by:Piotr Ɓowiec
Date:2004-09-13
Time limit:4s
Source limit:50000B
Memory limit:1536MB
Cluster: Cube (Intel G860)
Languages:All
Resource:6th Polish Olympiad in Informatics, stage 2