BYTESM2 - Philosophers Stone


One of the secret chambers in Hogwarts is full of philosopher’s stones. The floor of the chamber is covered by h × w square tiles, where there are h rows of tiles from front (first row) to back (last row) and w columns of tiles from left to right. Each tile has 1 to 100 stones on it. Harry has to grab as many philosopher’s stones as possible, subject to the following restrictions:

  • He starts by choosing any tile in the first row, and collects the philosopher’s stones on that tile. Then, he moves to a tile in the next row, collects the philosopher’s stones on the tile, and so on until he reaches the last row.
  • When he moves from one tile to a tile in the next row, he can only move to the tile just below it or diagonally to the left or right.
Given the values of h and w, and the number of philosopher’s stones on each tile, write a program to compute the maximum possible number of philosopher’s stones Harry can grab in one single trip from the first row to the last row.

Input

The first line consists of a single integer T, the number of test cases. In each of the test cases, the first line has two integers. The first integer h (1 <= h <= 100) is the number of rows of tiles on the floor. The second integer w (1 <= w <= 100) is the number of columns of tiles on the floor. Next, there are h lines of inputs. The i-th line of these, specifies the number of philosopher’s stones in each tile of the i-th row from the front. Each line has w integers, where each integer m (0 <= m <= 100) is the number of philosopher’s stones on that tile. The integers are separated by a space character.

Output

The output should consist of T lines, (1 <= T <= 100), one for each test case. Each line consists of a single integer, which is the maximum possible number of philosopher’s stones Harry can grab, in one single trip from the first row to the last row for the corresponding test case.

Example

Input:
1
6 5
3 1 7 4 2
2 1 3 1 1
1 2 2 1 8
2 2 1 5 3
2 1 4 4 4
5 2 7 5 1

Output:
32 	

//7+1+8+5+4+7=32

hide comments
jitendrakk: 2016-05-17 18:17:44

First DP problem with first time AC.. :)

atif_11: 2016-05-17 15:50:51

No need long long int....AC in 1st go with 0(n^2)

avisheksanvas: 2016-05-17 12:10:04

Try Miserman before or after this :)
Don't forget to use long long int :p

lt: 2016-03-24 08:57:58

Edit: I don't why it's getting tle in java and python, while the same algo in c++ gets submitted!

Argh!!! Input is not well formed, in python, if I take input character by character it gives TLE, if I take input line by line, it obviously gives run-time error. Don't know what to do! I'm using algo with complexity O(mn).

Last edit: 2016-03-24 09:10:25
pvsmpraveen: 2016-03-23 13:51:20

Got AC! with Dp-iterative and Dp-Recursion with Memorisation
Dp with Recursion gives TLE if not handled with care ;)

harshitdd120: 2016-03-10 20:41:23

Finally Solved my first DP problem

karthik1997 your comment was very helpful

Ram: 2016-03-07 15:26:42

Should have read the comments first.. Don't try it in python. Looks like input is malformed.

s6j4_10: 2016-02-15 13:24:22

Nice DP problem :)
got in 2nd attempt.

ajaysingh: 2016-02-06 18:17:35

My first DP problem :)

Aqib Ahmed J: 2016-01-29 18:40:54

AC in one go :) My 3rd DP problem :) Loving it !


Added by:Paritosh Aggarwal
Date:2009-02-21
Time limit:1s
Source limit:50000B
Memory limit:1536MB
Cluster: Cube (Intel G860)
Languages:ADA95 ASM32 BASH BF C CSHARP CPP C99 CLPS LISP sbcl LISP clisp D FORTRAN HASK ICON ICK JAVA LUA NEM NICE OCAML PAS-GPC PAS-FPC PERL PHP PIKE PRLG-swi PYTHON RUBY SCM guile SCM qobi ST TEXT WHITESPACE