COMDIV - Number of common divisors
You will be given T (T ≤ 106) pairs of numbers. All you have to tell is the number of common divisors between the two numbers in each pair.
Input
First line of input: T (Number of test cases)
In next T lines, each have one pair A B (0 < A, B ≤ 106)
Output
One integer describing number of common divisors between two numbers.
Example
Input: 3
100000 100000
12 24
747794 238336 Output: 36
6
2
hide comments
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ram_1897:
2015-09-25 09:21:26
use euclidean algorithm to compute gcd :) |
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Abdulsalam Abdo Helal:
2015-09-15 14:30:30
scanf and prinf is recommended to pass time
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Abishek:
2015-09-10 10:00:03
fast i/o and basic math ! |
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Medo:
2015-08-20 16:03:11
If you are sure of your complexity. Change to Printf scanf, and make sure all your variables are declared as int not long long. |
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prakash_reddy:
2015-08-18 15:56:38
Nice problem.... :) |
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sy_117:
2015-08-15 16:04:40
AC in first go.....Basic Math nothing else! |
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Indian Cyber Army (IndiShell):
2015-08-08 11:16:29
My code is running perfectly on Dev C++ but here its showing runtime error with floating point exception. I have used long long int. can you please point out the error to me.
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Sue:
2015-06-25 11:55:55
AC in the first go ~
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Varun Gambhir:
2015-06-15 12:58:44
All those getting TLE with sqrt(n) approach and using C/C++, use scanf printf instead of cin and cout. |
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excursionist:
2015-05-15 22:31:40
Loved it !!
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Added by: | Mir Wasi Ahmed |
Date: | 2010-10-31 |
Time limit: | 0.600s |
Source limit: | 50000B |
Memory limit: | 1536MB |
Cluster: | Cube (Intel G860) |
Languages: | All except: ASM64 |
Resource: | Own problem, used in UODA TST |