DIST - Distance
You are given the coordinates of N cities (xi,yi). Each city also has a popularity value, pi. You have to place a new city (x,y) such that the sum of distances of this new point from all the other given points is minimized.
Distance of the new point from a given city i is given by :
d = |xi - x| ^ pi + | yi - y | ^ pi
Input
There are multiple test cases.
First line contains the number of testcases.
Each testcases starts with the number N, the number of points.
This is followed by the descriptions of each in the format
xi yi pi
The input consists of only integers
Output
For each testcase, output the minimum distance obtained, with exactly 3 digits after the decimal point.
Example
Input:
1
3
1 2 0
4 5 1
2 4 2
Output: 4.500
Constraints
No. of testcases <= 10
N <= 10^5
|xi,yi| <= 1000
0 <= pi <= 3
hide comments
abhijith reddy d:
2011-02-11 14:19:30
Tip: Reading input itself takes 3+ secs. (scanf/printf) |
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numerix:
2011-02-09 16:38:56
... not for all languages |
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mike_nzk:
2011-02-09 07:41:20
time limit so large... |
Added by: | Kunal Jain |
Date: | 2011-02-07 |
Time limit: | 1.303s |
Source limit: | 50000B |
Memory limit: | 1536MB |
Cluster: | Cube (Intel G860) |
Languages: | All except: ASM64 |
Resource: | CodeCraft 11 |