DIVSUM - Divisor Summation
Given a natural number n (1 ≤ n ≤ 500000), please output the summation of all its proper divisors.
Definition: A proper divisor of a natural number is the divisor that is strictly less than the number.
e.g. number 20 has 5 proper divisors: 1, 2, 4, 5, 10, and the divisor summation is: 1 + 2 + 4 + 5 + 10 = 22.
Input
An integer stating the number of test cases (equal to about 200000), and that many lines follow, each containing one integer between 1 and 500000 inclusive.
Output
One integer each line: the divisor summation of the integer given respectively.
Example
Sample Input: 3 2 10 20 Sample Output: 1 8 22
Warning: large Input/Output data, be careful with certain languages
hide comments
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deisylix:
2020-07-13 00:57:34
say the wrong answer but I don't understand why |
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mrghasita:
2020-06-16 05:00:55
Python users getting TLE should use stdin and stdout |
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vikhyat_123:
2020-05-28 13:00:53
why it give run time error |
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deepshikha_14:
2020-05-12 10:50:11
getting right answers in my system(Just according to formula) still getting wrong ans here... what else should I take care of? |
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spyder_40:
2020-04-24 12:03:20
use i<=sqrt(num) to avoid TLE
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sonushahuji4:
2020-04-20 17:42:11
When I submit code in python3 for this problem, I get TLE but same logic when I write in cpp, it accepts. Why is this so? Last edit: 2020-04-20 18:51:41 |
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sanjeev30798:
2020-01-21 17:26:26
for n=1 output is 0 |
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trungvt:
2019-08-08 12:24:56
corner case: n = 1 |
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sanket17:
2019-08-02 15:17:47
same solution in c++ give wrong answer and in c it is Ac
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lamphong25:
2019-07-27 13:54:01
did anyone know name of file input output please tell me |
| Added by: | Neal Zane |
| Date: | 2004-06-10 |
| Time limit: | 3s |
| Source limit: | 5000B |
| Memory limit: | 1536MB |
| Cluster: | Cube (Intel G860) |
| Languages: | All |
| Resource: | Neal Zane |
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