DOPECNT - count frequency of digits
Young Dope was bored of finding whether a given number is palindromic or not. So he started another exercise described as follows. Given a number consisting of n digits, find the number of pairs of digits such that position[i] equals position[j] (1 ≤ i, j ≤ n).
Input
First line contains T, the number of test cases < 100.
Each test case contains a number with 1 ≤ length ≤ 105 and digits only between 0 and 9 both inclusive.
Output
Number of pairs of such digits.
Example
Input: 2 1234 777 Output: 4 9
Added by: | pankaj |
Date: | 2011-02-19 |
Time limit: | 1s-1.475s |
Source limit: | 50000B |
Memory limit: | 1536MB |
Cluster: | Cube (Intel G860) |
Languages: | All |
Resource: | harsh, DOPE 2011 |