GSS4 - Can you answer these queries IV


You are given a sequence A of N (N <= 100,000) positive integers. There sum will be less than 1018. On this sequence you have to apply M (M <= 100,000) operations:

(A) For given x, y, for each elements between the x-th and the y-th ones (inclusively, counting from 1), modify it to its positive square root (rounded down to the nearest integer).

(B) For given x, y, query the sum of all the elements between the x-th and the y-th ones (inclusively, counting from 1) in the sequence.

Input

Multiple test cases, please proceed them one by one. Input terminates by EOF.

For each test case:

The first line contains an integer N. The following line contains N integers, representing the sequence A1.. AN.
The third line contains an integer M. The next M lines contain the operations in the form "i x y". i=0 denotes the modify operation, i=1 denotes the query operation.

Output

For each test case:

Output the case number (counting from 1) in the first line of output. Then for each query, print an integer as the problem required.

Print an blank line after each test case.

See the sample output for more details.

Example

Input:
5
1 2 3 4 5
5
1 2 4
0 2 4
1 2 4
0 4 5
1 1 5
4
10 10 10 10
3
1 1 4
0 2 3
1 1 4

Output:
Case #1:
9
4
6

Case #2:
40
26

hide comments
aftershock007: 2024-09-26 06:00:55

Most annoying problem just replace cin with scanf and cout with printf and it works

yang114514: 2024-03-02 10:59:02

can anyone tell me how to download the data /kkk

rebel_roar: 2022-01-23 10:38:04

Please Can anyone tell me what is the meaning of these lines, without these lines my code giving TLE while updating
ll segmentSum = (r - l + 1);
if (segmentSum == tree[ind]) return;
Here l,r are the left and right edges of tree not the edges of updating segment.

vucuong2005: 2021-10-28 06:30:58

if you don't read the statement carefully, well...
when you input operations, namely "i x y", if x > y then you must swap x with y.

sicho_mohit: 2021-07-17 16:16:04

A small hint:
Just think how many times you can do square root of a particular number.
Just think can all the number after some operation in a segment becomes equal to 1.

o_oaikin: 2021-02-17 02:49:29

Notice every integres using long long , Not only the sum!!

o_oaikin: 2021-02-17 02:47:25

slove it! Nice!

o_oaikin: 2021-02-15 10:41:27

Damn it!

aryan12: 2020-10-04 13:05:22

AC in the second go!! Missed the (l > r) constraint in queries.

pcwallace: 2020-04-29 07:55:23

anyone get AC in java


Added by:Fudan University Problem Setters
Date:2008-05-21
Time limit:0.5s
Source limit:50000B
Memory limit:1536MB
Cluster: Cube (Intel G860)
Languages:All except: C99 ERL JS-RHINO PERL6
Resource:Own problem, used in ACM/ICPC Regional Contest, Shanghai 2011 preliminary