HPYNOSII - Happy Numbers II
The process of “breaking” an integer is defined as summing the squares of its digits. For example, the result of breaking the integer 125 is (12 + 22 + 52) = 30. An integer N is happy if after “breaking” it repeatedly the result reaches 1. If the result never reaches 1 no matter how many times the “breaking” is repeated, then N is not a happy number.
Task
Write a program that given an integer T (number of test cases) and T integers, determines for each number whether it is a happy number or not.
Constraints
1 ≤ T ≤ 1,080,000
2 ≤ N ≤ 2,147,483,647 (number for determining whether it is happy or not)
Input
The first line contains an integer T.
Next T lines contain an integer N for detemining whether it is happy or not.
Output
T lines containing a single integer N which is the number of times the process had to be done to determine that N is happy, or -1 if N is not happy.
Example
Input:
2
19
204
Output:
4
-1
Explanation
First test case:
- 19 : 12 + 92 = 82
- 82 : 82 + 22 = 68
- 68 : 62 + 82 = 100
- 100 : 12 + 02 + 02 = 1
The solution for 19 is 4 because we discovered that the integer 19 is happy after we repeated the process 4 times.
Second test case:
204 → 20 → 4 → 16 → 37 → 58 → 89 → 145 → 42 → 20 → 4 → 16 → 37 → 58 → 89 → 145 ...
204 is not a happy number because after breaking it several times the results start repeating so we can deduce that if we continue breaking it, the result will never reach 1.
hide comments
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nadstratosfer:
2018-04-08 03:37:02
Optimized (!) O(1) in PyPy gets 0.50 in the tutorial version, hence TLE here. Don't waste your time on this garbage, use INTEST for IO optimizations instead. |
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karthik1997:
2018-01-01 21:05:50
Man , used floyd cycle detection and all i could do is to solve it in 0.10s. Cant get below it . :( |
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coder_hsnake:
2016-08-30 13:12:45
wow same solution of happy number got me AC in one go!!!!! and this is no I/O race scanf and printf works fine |
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Piyush Kumar:
2016-06-24 20:05:35
So the difference between this and HYPNOS is just IO. :( |
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shantanu tripathi:
2015-08-29 21:25:16
fread_unlocked will work... very strict i/o...rest is precomputation :) |
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Ankit:
2015-08-18 16:25:51
use getchar_unlocked :) |
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:.Mohib.::
2015-08-01 17:42:54
Nice..!! |
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Aditya Kumar:
2015-06-29 11:12:26
finally AC.....
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ASHUTOSH DWIVEDI:
2015-06-25 23:11:36
hell of a problem
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Vipul Srivastava:
2015-06-20 14:00:45
My 2 different solutions one giving 1 for 1000000 and the other giving 2 for the same get AC. |
Added by: | Rofael Emil |
Date: | 2010-11-05 |
Time limit: | 1s |
Source limit: | 50000B |
Memory limit: | 1536MB |
Cluster: | Cube (Intel G860) |
Languages: | All except: ASM64 |
Resource: | (modified) Egyptian Olympiad in Informatics ( EOI ) 2009, August 14 - 21, Cairo |