IITWPC4D - Arrangement Validity
n persons are standing in a line. Height of each person is between 1 and n and height of each person is distinct.
You a given array A where A[i] denotes how many persons are before i_th person having heights greater than H[i]. eg. For person 2, person 1 is considered before him. If A is given to be [0, 1] then one valid arrangements of height could be [2, 1] as number of persons having height > 1 before 2 are 1 because H[1] > H[2]
You have to find out whether this array can be valid for some arrangement of persons. If you can uniquely do so, then find out the array H. Otherwise output -1.
Input
First line contains T : number of test cases. (1 <= T <= 20).
For each test First line contains an integer n. (1 <= n <= 10^5)
Next line contains n space separated integers denoting A[i]. (0 <= A[i] <= n)
Output
For each test case output single line
If there is a unique way of H. Then print n space separated integers in the line.
Otherwise output -1.
In starting of each test case also put "Test : testNumber" (without quotes). Note that there is a space before colon and one space after colon.
Example
Input: 2
3
0 1 1
3
0 1 0 Output: Test : 1
3 1 2
Test : 2
2 1 3
hide comments
sobir_bobiev:
2019-07-27 06:45:00
Can we really have multiple ways for H? |
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amulyagaur:
2018-03-02 14:52:58
pbds rocks! |
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RIVU DAS:
2014-05-24 07:35:05
Finally AC!! |
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007: Name stolen:
2014-03-25 09:49:01
@praveen123
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Ujjwal Prakash:
2014-02-08 21:59:34
Nice problem with good test cases. Similar problem gave AC but this gave TLE |
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praveen123:
2014-02-04 00:47:43
@bloody_looser Test data was wrongly uploaded, Updated now. |
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shiv prasad chabarval:
2014-02-04 00:46:16
is there any problem with i/o format. praveen123 plz tell me why i am getting WA |
Added by: | praveen123 |
Date: | 2014-01-31 |
Time limit: | 3s |
Source limit: | 50000B |
Memory limit: | 1536MB |
Cluster: | Cube (Intel G860) |
Languages: | All except: ASM64 |
Resource: | IITK ACA CSE online judge |