JNEXT - Just Next !!!
DevG likes too much fun to do with numbers. Once his friend Arya came and gave him a challenge, he gave DevG an array of digits which is forming a number currently (will be called as given number). DevG was challanged to find the just next greater number which can be formed using digits of given number. Now DevG needs your help to find that just next greater number and win the challenge.
Input
The first line have t number of test cases (1 <= t <= 100). In next 2*t lines for each test case first there is number n (1 <= n <= 1000000) which denotes the number of digits in given number and next line contains n digits of given number separated by space.
Output
Print the just next greater number if possible else print -1 in one line for each test case.
Note : There will be no test case which contains zero in starting digits of any given number.
Example
Input: 2 5 1 5 4 8 3 10 1 4 7 4 5 8 4 1 2 6 Output: 15834 1474584162
hide comments
rock_puneet:
2019-10-31 10:19:32
@owl_a same here |
|
abhishekv18:
2019-10-23 21:10:50
In case of sorting......use merge sort in place of quick sort
|
|
kumarpritam863:
2019-10-21 11:22:42
I have used stack with o(n) soln |
|
captain_thor0:
2019-07-09 16:05:14
How to solve this Problem Using Stack?? : ) |
|
nitin_uniyal21:
2019-07-02 12:45:37
accepted with python 3. Optimize your code |
|
hitesh87:
2019-05-23 18:29:32
Print array!! Don't print number Costed 2 WA |
|
annie181100:
2019-05-07 08:22:56
For an editorial, view this :
|
|
hardik712:
2019-05-02 12:24:19
why its TLE even though if we use next_permutation? |
|
sajanch:
2019-04-26 18:43:26
Why am I getting a TLE in linear time solution in Java? I have used Fast I/O too. Last edit: 2019-04-26 18:44:11 |
|
tensor08:
2019-04-25 15:29:56
Is there any way to do it in linear time or using Stack?
|
Added by: | ! include(L.ppt) |
Date: | 2012-08-31 |
Time limit: | 1.297s |
Source limit: | 50000B |
Memory limit: | 1536MB |
Cluster: | Cube (Intel G860) |
Languages: | All except: ASM64 |
Resource: | MNNIT OPC 31-08-2012 |