MBR - Multiplying by Rotation
Multiplication of natural numbers in general is a cumbersome operation. In some cases however the product can be obtained by moving the last digit to the front.
Example: 179487 * 4 = 717948
Of course this property depends on the number system you use, in the above example we used the decimal representation. In base 9 we have a shorter example:
17 * 4 = 71 (base 9)
as (9 * 1 + 7) * 4 = 7 * 9 + 1
Input
Each line consists of three numbers separated by a space: the base (<=36) of the number system, the least significant digit of the first factor, and the second factor. This second factor is one digit only hence less than the base. The input file ends with the standard end-of-file marker.
All Numbers in input are greater than 1 and will fit in the standard "int" data type. For base > 10 you can assume the digits to be 'A' ... 'Z'.
Note: Numbers in input may or may not be expressed using the above digits (refer example)
Output
Your program determines for each input line the number of digits of the smallest first factor with the rotamult property. Each line contains the answer for the corresponding input line.
Example
Input: 10 7 4 9 7 4 17 14 12 17 E C Output: 6 2 4 4
The last two inputs are actually the same.
hide comments
Ankit Jain:
2013-12-14 19:35:12
basic knowlwdge about multiplication is enough to solve this problem... |
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Prof_Utonium_ಉಮೆಶ್:
2010-10-07 07:25:04
This is similar to problem DOUBLE |
Added by: | SALVO |
Date: | 2010-05-29 |
Time limit: | 1s |
Source limit: | 50000B |
Memory limit: | 1536MB |
Cluster: | Cube (Intel G860) |
Languages: | All except: NODEJS OBJC PERL6 SQLITE VB.NET |
Resource: | UVA (own input) |