MINCOUNT - Move To Invert
A triangle made of coins of height h is as follows:
- It has h coins at the base and h-1 coins one level above base and so on. (Coins are placed as shown in the figure below.)
- At the top-most level there will be only one coin.
Now given h, the task is to invert this triangle by moving the minimum number of coins.
For example when h=4 triangle is:
For h=4 at least 3 coins must be moved to invert it.
Input
In the first line N will be given and then N lines follow with each line having a integer which is the height of triangle in that test case. (0 ≤ h < 1010.)
Output
For each test case output in a separate line the minimum number of moves required to invert the triangle. Output fits in long long data type.
Example
Input: 1 3 Output: 2
hide comments
killerz:
2012-05-31 07:59:22
just a simple math :)
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vD:
2012-03-23 12:51:04
Last edit: 2012-03-23 12:52:51 |
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(^@_^@):
2012-02-06 14:30:14
uses simple mathematics
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codecracker:
2012-02-06 14:29:46
it uses very simple mathematics...........
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Albert Chen:
2012-01-08 23:36:57
Yes... h can be 0. |
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MR. BEAN :
2011-12-12 14:31:56
answer for 100 is 1683 and for 10^10 is 7443294631478557525 !!! |
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sri:
2011-10-05 21:55:49
is the solution for 100 is 1875???
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Pavel Simo:
2011-07-22 08:46:37
weak test cases accepted with long long... |
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Vinay Chaudhary:
2011-07-21 21:15:41
WTH its not that complicated....analyse the output till 10 you will figure it out..:)..use scanf and printf instead of cin and cout |
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The Champ:
2011-07-16 10:16:12
why ERL is not allowed? |
Added by: | Abhilash I |
Date: | 2006-12-16 |
Time limit: | 1s |
Source limit: | 50000B |
Memory limit: | 1536MB |
Cluster: | Cube (Intel G860) |
Languages: | All except: ERL JS-RHINO |
Resource: | IIIT Hyderabad Local Programming Contest |