MULTQ3 - Multiples of 3


There are N numbers a[0], a[1] ... a[N - 1]. Initially all are 0. You have to perform two types of operations :

  1. Increase the numbers between indices A and B (inclusive) by 1. This is represented by the command "0 A B"
  2. Answer how many numbers between indices A and B (inclusive) are divisible by 3. This is represented by the command "1 A B".

Input

The first line contains two integers, N and Q. Each of the next Q lines are either of the form "0 A B" or "1 A B" as mentioned above.

Output

Output 1 line for each of the queries of the form "1 A B" containing the required answer for the corresponding query.

Sample

Input:
4 7
1 0 3
0 1 2
0 1 3
1 0 0
0 0 3
1 3 3
1 0 3

Output:
4
1
0
2

Constraints

1 ≤ N ≤ 100000
1 ≤ Q ≤ 100000
0 ≤ A ≤ B ≤ N - 1


hide comments
stranger: 2012-10-29 13:28:14

TLE. i am just tired of problems where io is almost always the only thing that you should care about

Ashok: 2012-08-31 10:38:28

used getchar_unlocked instead of scanf, still getting tle.

gourav: 2012-08-26 17:54:14

do we need to use segment tree or something like that

Amit: 2012-08-22 09:24:40

@Bruno : Thanks ( scanf -> getchar_unlocked() )

Rohit: 2012-07-10 11:31:34

gettinngg tle help!!

Rishi Mukherje: 2012-05-09 18:35:12

Why not increase time limit for languages like python?

Bruno Adami: 2011-10-13 20:23:14

The time limit is 1 second? o.O, the best solutions are greater than that!

Edit--

Its 1 sec per test case.. the time limit is too low, got accepted by changing scanf to getchar_unlocked..

Last edit: 2011-10-18 19:07:19
oldmonk: 2011-06-12 12:25:01

getting TLE suggest some method to make it faster

paddyHOD: 2011-02-10 11:00:15

my answer is correct
but it is giving time limit exceeded

Anil Kishore: 2010-09-28 07:05:58

yes it is, thats why the first query "1 0 3" ( how many of A[0..3] are divisble by 3 ) returns 4 ( all 0s initially )


Added by:Varun Jalan
Date:2010-09-12
Time limit:1s
Source limit:50000B
Memory limit:1536MB
Cluster: Cube (Intel G860)
Languages:All except: NODEJS OBJC VB.NET
Resource:own problem