PIBO2 - Fibonacci vs Polynomial (HARD)
Define a sequence Pib(n) as following
- Pib(0) = 1
- Pib(1) = 1
- otherwise, Pib(n) = Pib(n-1) + Pib(n-2) + P(n)
Here P is a polynomial.
Given n and P, find Pib(n) modulo 1,111,111,111.
Maybe you should solve PIBO before this task, it has lower constraints.
Input
First line of input contains two integer n and d (0 ≤ n ≤ 109, 0 ≤ d ≤ 10000), d is the degree of polynomial.
The second line contains d+1 integers c0,c1 … cd, represent the coefficient of the polynomial (Thus P(x) can be written as Σcixi). 0 ≤ ci < 1,111,111,111 and cd ≠ 0 unless d = 0.
Output
A single integer represents the answer.
Example
Input: 10 0 0 Output: 89
Input: 10 0 1 Output: 177
Input: 100 1 1 1 Output: 343742333
hide comments
suhash:
2020-08-10 16:50:17
Looks like the time limit is a bit strict for smaller cases. My solution got TLE multiple times before getting AC [ID: 26404488] (total runtime: 2.24 sec). Here are the run times of my solution in the worst case for different values of d (n = 10^9, ci = 1111111110 for all 'i'):
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eugenio:
2014-11-18 19:39:03
I've learnt so many things to tackle this one (even though I haven't used all of them)... Beautiful problem :) Last edit: 2014-11-18 19:40:07 |
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(Tjandra Satria Gunawan)(曾毅昆):
2014-11-13 13:25:55
Last Position! :p
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Federico Lebrón:
2013-05-27 21:48:38
Hrm, this seems pretty hard. I thought with a 0.01s runtime in PIBO and O(d) memory it'd be good enough, but apparently it's not :s
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Francky:
2013-03-04 19:21:22
It was great to solve this hard edition, I did my best with O(d) memory print. ;-)
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Added by: | Michael Kharitonov |
Date: | 2013-02-28 |
Time limit: | 0.100s-10s |
Source limit: | 50000B |
Memory limit: | 1536MB |
Cluster: | Cube (Intel G860) |
Languages: | All except: ASM64 |