TCONNUM - Simple Numbers Conversion
Every integer number n is represented in positional number system of base r by a sequence of digits 0 ≤ di < r, so the value is equal to:
n = d0 + r * d1 + r2 * d2 + r3 * d3 + ...
Your task is to convert a given number in r-base represantation into s-base representation, for example: decimal 231 into binary 11100111. Assume that r ≤ 36 and the digits are 0,1,2,3,4,5,6,7,8,9, A, B, C, D, E, F, G, H, I, J, K, L, M, N, O, P, Q, R, S, T, U, V, W, X, Y, Z.
Input
N [the number of series ≤ 1000]
n r s [n ≤ 101000, r,s ≤ 36]
Output
n [s-base representation of number n]
Text grouped in [ ] does not appear in the input and output file.
Example
Input: 3 231 10 2 ABC 15 10 XYZ 36 2 Output: 11100111 2427 1010101111111011
Test cases
There are five categories of the input data:
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Test case 1: (1 pt), r = 2 and s = 10, or conversely, n≤ 109, N = 100,
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Test case 2: (1 pt), 2 ≤ r,s ≤ 10, n≤109, N = 1000,
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Test case 3: (1 pt), 2 ≤ r,s ≤ 36, n≤ 109, N = 1000,
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Test case 4: (3 pts), 2 ≤ r,s ≤ 10, n≤ 101000, N = 1000,
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Test case 5: (4 pts), 2 ≤ r,s ≤ 36, n≤ 101000, N = 1000.
Added by: | mima |
Date: | 2004-10-13 |
Time limit: | 1s-5s |
Source limit: | 5000B |
Memory limit: | 1536MB |
Cluster: | Cube (Intel G860) |
Languages: | ASM32 BF C C++ 4.3.2 CPP C99 PAS-GPC PAS-FPC |