TETRA - Sphere in a tetrahedron
Of course a Sphere Online Judge System is bound to have some tasks about spheres. So here is one. Given the lengths of the edges of a tetrahedron calculate the radius of a sphere inscribed in that tetrahedron (i.e. a sphere tangent to all the faces).
Input
Number N of test cases in a single line. (N ≤ 30) Each of the next N lines consists of 6 integer numbers -- the lengths of the edges of a tetrahedron separated by single spaces. The edges are not longer than 1000 and for the tetrahedron WXYZ, the order of the edges is: WX, WY, WZ, XY, XZ, YZ.
Output
N lines, each consisting of a real number given with four digits decimal precision equal to the radius of a sphere inscribed in the given tetrahedron.
Example
Input: 2 1 1 1 1 1 1 1000 999 998 5 5 6 Output: 0.2041 1.4189
hide comments
Alex Anderson:
2012-06-03 21:01:10
@Pathan
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Pathan Salman Khan:
2012-02-17 12:02:50
Irregular tetrahedrons don't have one common sphere tangent to all the faces. Please check. You can ask for maximum contained sphere, though. |
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Peutri:
2010-09-05 13:36:55
There are extra lines past the N test cases. |
Added by: | Adam Dzedzej |
Date: | 2004-05-11 |
Time limit: | 1s |
Source limit: | 50000B |
Memory limit: | 1536MB |
Cluster: | Cube (Intel G860) |
Languages: | All except: NODEJS PERL6 VB.NET |