UPDATEIT - Update the array !
You have an array containing n elements initially all 0. You need to do a number of update operations on it. In each update you specify l, r and val which are the starting index, ending index and value to be added. After each update, you add the 'val' to all elements from index l to r. After 'u' updates are over, there will be q queries each containing an index for which you have to print the element at that index.
Input
First line consists of t, the number of test cases. (1 <= t <= 10)
Each test case consists of "n u", number of elements in the array and the number of update operations, in the first line (1 <= n <= 10000 and 1 <= u <= 100000)
Then follow u lines each of the format "l r val" (0 <= l, r < n, 0 <= val <=10000)
Next line contains q, the number of queries. (1 <= q <= 10000)
Next q lines contain an index (0 <= index < n)
Output
For each test case, output the answers to the corresponding queries in separate lines.
Example
Input: 1
5 3
0 1 7
2 4 6
1 3 2
3
0
3
4
Output:
7
8
6
hide comments
___Durgesh___:
2015-08-25 09:41:53
learnt a new approach :) |
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SANDEEP KUMAR:
2015-08-21 20:20:58
Ac in one go..Used prefix sum..O(n) |
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screw_1011:
2015-08-20 07:11:55
And when you think of segtrees and BIT , but oops, suddenly a 15 line code gives you AC :) O(n) :P |
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SangKuan:
2015-08-18 04:11:28
ac with BIT,want to know the O(n) method |
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anuveshkothari:
2015-07-31 20:27:35
learned something new about updating the array.. |
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sai krishna:
2015-07-28 06:29:03
Got AC with Both BIT and Segment tree+Lazy Propogation |
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:.Mohib.::
2015-07-26 17:24:46
Nice que...!! |
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sumit2893:
2015-06-16 03:31:46
This can help..https://kartikkukreja.wordpress.com/2013/12/02/range-updates-with-bit-fenwick-tree/
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shuks:
2015-06-03 13:56:15
How to solve using BIT?
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Arpan Mukherjee:
2015-05-21 22:02:10
My 1st BIT :) finally AC :) learnt a new DS :) |
Added by: | Pandian |
Date: | 2013-10-15 |
Time limit: | 1s |
Source limit: | 50000B |
Memory limit: | 1536MB |
Cluster: | Cube (Intel G860) |
Languages: | All except: ASM64 |
Resource: | Own |