ZSUM - Just Add It

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For two given integers n and k find (Zn + Zn-1 - 2Zn-2) mod 10000007, where Zn = Sn + Pn and Sn = 1k + 2k + 3k + … + nk and Pn = 11 + 22 + 33 + … + nn.

Input

There are several test cases (≤ 10000). In each case two space separated positive integers n and k are given.
For last test case n and k are given as 0 0, which is not to be processed.

Constraints

1 < n < 200000000
0 < k < 1000000

Output

For each case print the asked value in separate line.

Example

Input:
10 3
9 31
83 17
5 2
0 0

Output:
4835897
2118762
2285275
3694

hide comments
coolboy7: 2020-07-26 19:26:17

it's binary exponentiation

ks_r: 2020-07-23 13:08:28

AC In One GO !! :)

ashish_2495: 2020-06-08 18:05:05

I am using binary exponention and got sample results but the spoj shows tle...
can anyone tell me what is the formula for 1^k+2^k+3^k....n^k......

md_yasin: 2020-05-22 10:39:16

AC in one go!!! :v be careful to use long long and calculate power

deependra_18: 2020-04-12 14:10:25

thanks @sicklesplit for pointing 1e7+7 is not a prime .

izrail: 2020-04-09 17:18:45

n^k+2(n-1)^k+2(n-1)^(n-1)+n^n careful about mod and evaluate this exp.

subodh898: 2019-10-28 13:44:01

just solve the final relation given in terms of n and use binary exponentiation. Also careful about the mod, it is 1e7+7.

destiny_gamer: 2019-10-01 13:54:45

AC in one go! Finaally!

a_l_o_n_e: 2019-08-29 16:27:05

AC in one go!!!

sicklesplit: 2019-08-22 16:02:19

Reemember that 1e7+7 is not prime.


Added by:Manohar Singh
Date:2011-09-04
Time limit:1s
Source limit:50000B
Memory limit:1536MB
Cluster: Cube (Intel G860)
Languages:All except: ASM64
Resource:Manohar Singh