GCD2 - GCD2


Frank explained its friend Felman the algorithm of Euclides to calculate the GCD of two numbers. Then Felman implements it algorithm

int gcd(int a, int b)
{
	if (b==0)
		return a;
	else
		return gcd(b,a%b);
}
and it proposes to Frank that makes it but with a little integer and another integer that has up to 250 digits.

Your task is to help Frank programming an efficient code for the challenge of Felman.

Input

The first line of the input file contains a number representing the number of lines to follow. Each line consists of two number A and B (0 <= A <= 40000 and A <= B < 10^250).

Output

Print for each pair (A,B) in the input one integer representing the GCD of A and B.

Example

Input:
2
2 6
10 11

Output:
2
1

Source limit is 1,000 Bytes.


hide comments
mafia_987: 2023-04-08 21:58:55

make cases if a==0 return b else first calculate b%a and finally take gcd with a.really very easy problem just have to think of this intuition

kumar_anubhav: 2020-06-14 11:24:21

Nice Ques with basic Division Mathematics :) AC !!

this_variable: 2020-06-01 07:33:15

No java :(

dreamanddead: 2020-05-12 10:18:35

1000 Bytes for cpp, how to do that?

darker__space: 2020-01-21 13:56:42

if u r doing brute force then think another short trick or method...for sure it exists

roni_roy18: 2019-06-01 08:57:44

So easy using string in cpp :)
AC in one go, also in 0.00 sec :)

Last edit: 2019-06-01 08:58:41
sea_26: 2018-11-26 18:45:17

Very easy with string in cpp.If you use char array size then fixed 252 because 10^250.

malcolm123_ssj: 2018-11-17 18:54:59

don't think much. use python to solve such questions

prachij: 2018-10-03 20:57:34

AC in one go in Python 3 with 4 lines of code :D

mynk322: 2018-09-19 15:41:38

REMEMBER!!!!
gcd of a,0 is a.
gcd of 0,b is b.
cost me 2 WA!!


Added by:Frank Rafael Arteaga
Date:2008-08-04
Time limit:1s
Source limit:1000B
Memory limit:1536MB
Cluster: Cube (Intel G860)
Languages:All except: C99 LISP sbcl LISP clisp ERL JAVA JS-RHINO NODEJS PERL PERL6 PHP PYTHON RUBY VB.NET
Resource:My own Resource