In this problem you will be given a half-circle. The half-circle’s radius is r. You can take any point A on the half-circle and draw 2 lines from the point to the two sides of the diameter(AB and AC). Let the sum of square of one line’s length and the other line’s length is s

Like in the figure s = AB² + AC. And BC = 2r.

Now given r you have to find the maximum value of s. That is you have to find point A such that AB² + AC is maximum.

Input

First line of the test case will be the number of test case T (1 ≤ T ≤ 1000). Then T lines follows. On each line you will find a integer number r (1 ≤ r ≤ 1000000); each representing the radius of the half-circle.

Output

For each input line, print a line containing "Case I: ", where I is the test case number and the maximum value of s. Print 2 digit after decimal (Errors should be less then .01).

Example

Sample Input:
1
1

Sample Output:
Case 1: 4.25

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	bigBOSS: 2012-09-28 08:48:40 too simple......if u know a bit of maths......ac in first attempt
	Shubham: 2012-08-03 04:37:09 @tjandra agree @darky1 disagree
	Fish3R: 2012-06-30 19:49:11 Use long long and use lf to avoid WA...
	marwan akkad: 2012-06-22 20:05:14 Brilliant problem, it reminds me of my baccalaureate Thanks Muhammad Ridowan
	stranger: 2012-06-15 14:01:14 At least I've learned smth new about java's casting
	:): 2012-06-13 07:11:51 oh no i am getting TLE..used %Lf for answer and long long int for radius then also
	gabber: 2012-04-17 08:47:09 very easy just see the output formatting cost me three wa
	Darky: 2012-04-14 16:19:39 Somehow python gives wrong answer to this one.
	(Tjandra Satria Gunawan)(曾毅昆): 2012-03-24 18:20:53 i can solve this problem without using floating point or double... just integer with few math tricks :)
	ginnipkj: 2012-03-11 16:17:59 i totally agree with JVR and it is a bonus Question