In this problem you will be given a half-circle. The half-circle’s radius is r. You can take any point A on the half-circle and draw 2 lines from the point to the two sides of the diameter(AB and AC). Let the sum of square of one line’s length and the other line’s length is s

Like in the figure s = AB² + AC. And BC = 2r.

Now given r you have to find the maximum value of s. That is you have to find point A such that AB² + AC is maximum.

Input

First line of the test case will be the number of test case T (1 ≤ T ≤ 1000). Then T lines follows. On each line you will find a integer number r (1 ≤ r ≤ 1000000); each representing the radius of the half-circle.

Output

For each input line, print a line containing "Case I: ", where I is the test case number and the maximum value of s. Print 2 digit after decimal (Errors should be less then .01).

Example

Sample Input:
1
1

Sample Output:
Case 1: 4.25

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	sukriti_verma: 2015-08-01 23:49:00 int radius gave WA float radius gave WA double gives AC -.-
	Shreyas Dixit: 2015-07-21 21:42:18 basic trigonometry Last edit: 2015-07-21 21:42:49
	ROHIT Kumar: 2015-07-12 16:11:13 can anybody tell why it was not working with float... Last edit: 2015-07-12 16:22:54
	ROHIT Kumar: 2015-07-12 16:08:30 ac after 5 wa..use double... Last edit: 2015-07-12 16:22:12
	Shantanu Banerjee: 2015-07-03 07:02:40 This stupid Ques caused me 5 WA's, Hell Frustated, WA in C AC in C++
	r0bo_dart: 2015-06-18 11:05:34 Damn easy question. Don't waste time here.
	kobe24: 2015-05-30 14:18:49 stupid question
	BRAIN: 2015-04-29 03:50:31 4 * r * r + 0.25 ( using floating point )
	_R0b_: 2015-04-20 22:46:05 is it my answer's correct format ? 3 1 Case 1: 4.25 1000 Case 2: 4e+06 100000 Case 3: 4e+10
	NIKHIL KUMAR SINGH: 2015-04-18 19:05:20 Don't know that ....When i submitted in python got 4 WA's and AC in one go in C++