MAXLN - THE MAX LINES

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In this problem you will be given a half-circle. The half-circle’s radius is r. You can take any point A on the half-circle and draw 2 lines from the point to the two sides of the diameter(AB and AC). Let the sum of square of one line’s length and the other line’s length is s

Like in the figure s = AB2 + AC. And BC = 2r.

Now given r you have to find the maximum value of s. That is you have to find point A such that AB2 + AC is maximum.

Input

First line of the test case will be the number of test case T (1 <= T <= 1000). Then T lines follows. On each line you will find a integer number r (1 <= r <= 1000000); each representing the radius of the half-circle.

Output

For each input line, print a line containing "Case I: ", where I is the test case number and the maximum value of s. Print 2 digit after decimal (Errors should be less then .01).

Example

Sample Input:
1
1

Sample Output:
Case 1: 4.25

hide comments
ash_demon8: 2018-04-05 18:13:27

AC in one go...... with 4 lines of code:)

abhinav__: 2018-04-02 17:31:08

Use double as the data type and make sure to type cast your solution when printing

prateek_imkp1: 2018-03-30 07:16:32

Use long long int _/\_

ayusofayush: 2018-02-23 14:18:51

simple differentiation and use setprecision() ....only maths

Divyam Shah: 2018-02-09 17:24:19

@Nani the value of roots is not imaginary, for AC=0.5 we get "AC^2 - AC = -0.25".

vkash: 2018-01-03 10:55:20

4 lines of code...easy 1 :)

nani: 2017-12-27 19:37:56

There seems to be some loophole in the question, pythagorean theorem AB^2 + AC^2 = BC^2. For sample input AB^2 + AC^2 = 4, but how will AB^2 + AC = 4.25 this tends to be AC^2 - AC = -0.25 which in return leads to imaginary values of AC. Please clarify me if I am missing anything?

techventer_936: 2017-06-30 23:06:05

Simple AC in one go :)
look for input data type and precision.

Anand Kumar: 2017-06-25 10:57:14

took time.. but finally got it...

shalini6: 2017-06-08 14:06:41

Use s = AB^2 + AC and pythagoras theorem AB^2 + AC^2 = (2r)^2(traingle in a semi circle is right angled)
Then differentiate. Simple maxima


Added by:Muhammad Ridowan
Date:2011-03-28
Time limit:1s-1.679s
Source limit:50000B
Memory limit:1536MB
Cluster: Cube (Intel G860)
Languages:All except: ASM64
Resource:Own Problem(used for CSE,University of Dhaka, Newbies Contest)